Say you’ve got the following log files with the oldest entries in myapi.log.3.gz:<\/p>\n
myapi.log.1.gz
\n myapi.log.2.gz
\n myapi.log.3.gz<\/p>\n
If you want to ‘grep’ them for a string, in order of date, oldest to newest, there’s no need to extract them one at a time, and there’s no need to concatenate the files first. Use sort to put the files in the proper order, and zgrep to search though the compressed files.<\/p>\n
Here’s how to order the file list:<\/p>\n
ls myapi.log.*.gz | sort -nr -t . -k 3,3<\/p>\n
Here’s how to ‘zgrep’ them in the proper order:<\/p>\n
ls myapi.log.*.gz | sort -nr -t . -k 3,3 | xargs zgrep “404”<\/p>\n","protected":false},"excerpt":{"rendered":"
Say you’ve got the following log files with the oldest entries in myapi.log.3.gz: myapi.log.1.gz myapi.log.2.gz myapi.log.3.gz If you want to ‘grep’ them for a string, in order of date, oldest to newest, there’s no need to extract them one at a time, and there’s no need to concatenate the files first. Use sort to put … <\/p>\n